Wednesday, 21 February 2018

Determining Buoyant Forces

Exploration Lab of Buoyant Forces

1. String
2. 1000 - 10g standard masses
3. Newton Scale
4. 250g graduated cylinder
5. 500 mL beaker

Table of Measurements
Measured amount of water: 500mL and 400mL

Object                                 Weight in air (N)   Weight in water (N)   Buoyant force (N)
1000g Standard Mass              8.5N                               6N                                 2.5N   
500g Standard Mass                 5N                                  4N                                  1N
200g Standard Mass                 2N                                 1.5N                               0.5N
100g Standard Mass                  1N                                 0.8N                              0.2N
50g Standard Mass                    0.5N                             0.4N                              0.1N
25g Standard Mass                   0.25N                           0.2N                             0.05N
10g Standard Mass                  0.125N                           0.1N                            0.025N

Object                              Volume of Displaced water (mL)                Weight of Displaced Water
1000g Standard Mass                           350mL                                                             3.43N
500g Standard Mass                             50mL                                                               0.49N
200g Standard Mass                             10mL                                                              0.098N
100g Standard Mass                               3mL                                                              0.0294N
50g Standard Mass                                1.5mL                                                             0.0147N
25g Standard Mass                               0.75mL                                                           0.00735N
10g Standard Mass                               0.375mL                                                        0.003675N

Analize and Conclude

1. Observing; What force is responsible for the difference between the weight of each object in the air and its apparent weight in water?
 -- Buoyant force

2. Analyzing Data; How is buoyant force related to the weight of water displaced?
 -- Each millilitre of water has a weight of 0.0098 newtons.

3. Forming Operational Definitions; Define buoyant force and describe two ways you can measure it or calculate it.
 -- Buoyant force is a force that gives an ability to float in a fluid (water and air). We can measure it by using a measurement object with the object you want to measure and place it in water. The buoyant force would be weight in air minus the apparent weight in water.

4. Drawing Conclusions; Explain what causes an object to sink or to float, using the terms buoyancy, weight, force, density and gravity.
 -- Buoyancy is a force that opposes gravity which allows something to float in a fluid - floating, however, if there is no oxygen / air in those objects, it will sink because of how gravity works with force.

Wednesday, 14 February 2018

My Time Capsule

How Does Water Bend?

Water and Balloon Lab

We had a lab which we tried to bend water.

1. Water
2. Beaker
3. Funnel
4. Balloon filled with air
5. Hair / Sweater

We first experimented with only a balloon with no electrostaticity, and poured water beside the balloon, it doesn't attract water to the balloon. Secondly, we rubbed the balloon with our hair and tried to pour water beside it again, the water bends! 

The Water Bends!

Testing out how much electrostaticity there is in the balloon

Wednesday, 10 January 2018

Vector Mapping With Kru Gary

 Vector Mapping

Starting point; Southern flagpole of PHS
1. Walk to the south 13 steps
2. East 24 steps
3. South 6 steps
4. north 17 steps
5. Upper Floor
6. West 4 steps
7. North 22 steps
8. West 38 steps
9. Upper floor
10. South 3 stpes
11. West 16 steps.
12. South 51 steps

End Point: M4 / 401 Room

Wednesday, 15 November 2017

Exploring Color

Colour Lab

White is the result of all colors of the visible spectrum being reflected from an object. Black is the result of all colors of the spectrum being absorbed by an object.

- 1 color paddles set
- 1 flashlight
- 1 dual hand lens
- 1 sheet of white copy paper

1st Activity:
We use the color paddles to mix 2 of them up (Red+Green, Red+Blue, Blue+Green). Which is to try to see whether which one mixes up to gain another color. 

Red + Blue
= Red - Pink 

Image result for what color is blue and green combined

Blue + Green
= Cyan green

Red + Green
= Yellow

All of the colors combined
= Yellowish white.

Activity 2: Viewing colored objects through color paddles

This is First and Non, I took a picture of them whilst using color paddles.

Wednesday, 13 September 2017

Crystallisation Lab

-- Crystallisation Lab --

1)  Why do we add salt to the ice?
- Adding salt lowers the freezing temperature of water and wintry ingredients. Therefore, as ice melts - it lowers the temperature and make the ingredients freeze.

2)  Why do we add the cookies and other things, only after the milk has frozen slightly
- If we add the cookies and other toppings, it would likely to slow down the freezing of the ice.

3)  What are two factors that affect the freezing you think?
- When we shake the ice and scrape the ice bag to make the ingredients freeze.
- Furthermore salt and sugar may affect the factors of freezing.

4)  Why do you need a bit of air in the bag?
- We need to make the ice freeze fast, therefore we need a bit of air to make it easier to freeze.

Wednesday, 7 June 2017

-- Skillz Practice --

Skill Practice Key Concepts

Calculate the density of each of your mineral samples. How could you use the densities to identify the minerals?

= We will know it's shape and size of the mineral, also the weight of grams/kilograms. We also can identify the liquid volume too.

Key Concept: Would density or color be more useful in identifying a particular mineral? Explain your answer.

= I think both color and density has both advantages, they can be useful to be identified and to find the important parts of the mineral.